I'm getting an error when trying to define a pattern synonym based on a GADT that has a type-level list.
I managed to boil it down to this example:
{-# LANGUAGE GADTs #-}
{-# LANGUAGE KindSignatures #-}
{-# LANGUAGE DataKinds #-}
{-# LANGUAGE TypeOperators #-}
{-# LANGUAGE PatternSynonyms #-}
module Example where
data L (as :: [*]) where
L :: a -> L '[a]
pattern LUnit = L ()
Gives me:
Example.hs:11:17:
Couldn't match type ‘a’ with ‘()’
‘a’ is a rigid type variable bound by
the type signature for Example.$bLUnit :: (t ~ '[a]) => L t
at Example.hs:11:17
Expected type: L t
Actual type: L '[()]
In the expression: L ()
In an equation for ‘$bLUnit’: $bLUnit = L ()
Example.hs:11:19:
Could not deduce (a ~ ())
from the context (t ~ '[a])
bound by a pattern with constructor
L :: forall a. a -> L '[a],
in a pattern synonym declaration
at Example.hs:11:17-20
‘a’ is a rigid type variable bound by
a pattern with constructor
L :: forall a. a -> L '[a],
in a pattern synonym declaration
at Example.hs:11:17
In the pattern: ()
In the pattern: L ()
Is this a bug, or am I doing something wrong?
Thanks to dfeuer's comment and this ticket, I was able to get my example code to compile by adding a type signature to the pattern definition:
{-# LANGUAGE GADTs #-}
{-# LANGUAGE KindSignatures #-}
{-# LANGUAGE DataKinds #-}
{-# LANGUAGE TypeOperators #-}
{-# LANGUAGE PatternSynonyms #-}
module Example where
data L (as :: [*]) where
L :: a -> L '[a]
pattern LUnit :: L '[()]
pattern LUnit = L ()
Which also generalizes nicely to polymorphic patterns
data F (fs :: [* -> *]) a where
F :: f a -> F '[f] a
pattern FId :: a -> F '[Identity] a
pattern FId a = F (Identity a)
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