Logo Questions Linux Laravel Mysql Ubuntu Git Menu
 

Pattern matching equivalent variables in Haskell, like in Prolog

In prolog, we can do something like the following:

myFunction a (a:xs) = ...

This is, when the 1st argument of myFunction is the same as the first item of the list that's in the 2nd argument, this function will evaluate to ....

My question now is... how to accomplish a similar thing in Haskell? I have the idea that Prolog's Pattern Matching is more expressive than Haskell's. I've been trying to code that in Haskell and I'm having trouble -- either I am using invalid syntax or the above trick will simply not do.

like image 852
devoured elysium Avatar asked Nov 04 '10 00:11

devoured elysium


2 Answers

Haskell doesn't do this kind of "variable matching". You'll have to explicitly put a guard on:

myFunction a (x:xs)
    | x == a = ...
like image 94
porges Avatar answered Sep 24 '22 21:09

porges


Haskell doesn't do unification of variables, as Prolog does. As the Haskell 98 report says,

The set of patterns corresponding to each match must be linear---no variable is allowed to appear more than once in the entire set.

You can of course name the variables, and state they must also be equal:

f a (b:_) | a == b = ...

Interestingly, Agda does let information flow across patterns like this, and introduces a special notation f x (.x:_) to say that this x must be that x.

like image 22
Don Stewart Avatar answered Sep 24 '22 21:09

Don Stewart