passing php variable in onClick function

Question

I want to pass the php variable value in onClick function. When i pass the php variable, in the UI i am getting the variable itself instead I need the value in the variable.

Below is code snippet, please help me.

<?php
print '<td>'; 
$node  = $name->item(0)->nodeValue;
$insert= "cubicle"."$node<br>";
Echo '<a href= "#" onClick= showDetails("$node");>'. $insert .'</a> ';
print '</td>';
?>

Answer 1

Variable parsing is only done in double quoted strings. You can use string concatenation or, what I find more readable, printf ^[docs]:

printf('<a href= "#" onClick="showDetails(\'%s\');">%s</a> ', $node, $insert);

The best way would be to not echo HTML at all, but to embed PHP in HTML:

<?php
    $node  = $name->item(0)->nodeValue;
    $insert = "cubicle" . $node;
?>

<td> 
    <a href= "#" onClick="showDetails('<?php echo $node;?>');">
        <?php echo $insert; ?> <br />
    </a>
</td>

You have to think less about quotes and debugging your HTML is easier too.

Note: If $node is representing a number, you don't need quotations marks around the argument.

Answer 2

you shouldn't be wrapping $node in '"':

Echo '<a href= "#" onClick= showDetails($node);>'. $insert .'</a> ';

If you want the value of $node to be in a string, thn i would do:

Echo '<a href= "#" onClick= showDetails("' . $node. '");>'. $insert .'</a> ';