Passing parameters to XSLT Stylesheet via .NET

Question

I'm trying to pass a parameter to an XSLT stylesheet, but all i'm getting is an empty xml document when the document is transformed using XSlCompiledTransform.

This is the C# method used to add the parameters(after adding in people's suggestions)

private static void CreateHierarchy(string manID)     {          string man_ID = manID;          XsltArgumentList argsList = new XsltArgumentList();         argsList.AddParam("Boss_ID","",man_ID);          XslCompiledTransform transform = new XslCompiledTransform();         transform.Load("htransform.xslt");          using (StreamWriter sw = new StreamWriter("output.xml"))         {             transform.Transform("LU AIB.xml", argsList, sw);         }        } 

and here is the stylesheet. The parameter i'm passing in is 'Boss_ID'

   <?xml version="1.0" encoding="utf-8"?>    <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">    <xsl:output method="xml" indent="yes" />    <xsl:template match="OrgDoc">      <xsl:param name="Boss_ID"></xsl:param>     <xsl:processing-instruction name="xml-stylesheet">     <xsl:text>type="text/xsl" href="..\styles\orgcharts.xsl" </xsl:text>   </xsl:processing-instruction>     <OrgDoc>       <xsl:for-each select="PosDets[@OC_Man = $Boss_ID]">       <PosDets OC_Pos="{@OC_Pos}" OC_Sub="{@OC_Sub}" OC_Man="{@OC_Man}" OC_Ttl="{@OC_Ttl}" OC_Rnk="{@OC_Rnk}" OC_Bdg="{@OC_Bdg}" OC_Fnd="{@OC_Fnd}"   OC_OL3="{@OC_OL3}"    OC_Tmp="{@OC_Tmp}">           <xsl:apply-templates select="../PosDets">             <xsl:with-param name="mgrid" select="@OC_Pos"/>           </xsl:apply-templates>         </PosDets>         </xsl:for-each>     </OrgDoc>   </xsl:template>   <xsl:template match="PosDets" >      <xsl:param name="mgrid" />     <xsl:if test="@OC_Man=$mgrid" >       <PosDets OC_Pos="{@OC_Pos}" OC_Sub="{@OC_Sub}" OC_Man="{@OC_Man}" OC_Ttl="{@OC_Ttl}" OC_Rnk="{@OC_Rnk}" OC_Bdg="{@OC_Bdg}" OC_Fnd="{@OC_Fnd}"   OC_OL3="{@OC_OL3}"    OC_Tmp="{@OC_Tmp}">         <xsl:apply-templates select="../PosDets">           <xsl:with-param name="mgrid" select="@OC_Pos"/>         </xsl:apply-templates>       </PosDets>       </xsl:if>   </xsl:template>      </xsl:stylesheet>   

I can't post all of the input document as it's confidential info, but here's a brief sanitised version

<OrgDoc><PosDets OC_Pos="161" OC_Man="9" OC_Ttl="Boss" OC_Rank="" OC_OL3="LU AIB" OC_Bdg="Has Budget" OC_Fnd="Payroll" OC_Sub="" OC_Tmp="" /><PosDets OC_Pos="190" OC_Man="161" OC_Ttl="Boss" OC_Rank="" OC_OL3="LU AIB" OC_Bdg="Has Budget" OC_Fnd="Payroll" OC_Sub="" OC_Tmp="" /><PosDets OC_Pos="199" OC_Man="190" OC_Ttl="Boss" OC_Rank="" OC_OL3="LU AIB" OC_Bdg="Has Budget" OC_Fnd="Payroll" OC_Sub="" OC_Tmp="" /></OrgDoc> 

Can anyone help?

Thanks

Answer 1

You need to define the parameter within your XSLT and you also need to pass the XsltArgumentList as an argument to the Transform call:

private static void CreateHierarchy(string manID) {     string man_ID = manID;      XsltArgumentList argsList = new XsltArgumentList();     argsList.AddParam("Boss_ID", "", man_ID);      XslCompiledTransform transform = new XslCompiledTransform(true);     transform.Load("htransform.xslt");      using (StreamWriter sw = new StreamWriter("output.xml"))     {         transform.Transform("LU AIB.xml", argsList, sw);     } } 

Please note that the xsl:param must be defined below the xsl:stylesheet element:

<?xml version="1.0" encoding="utf-8"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">   <xsl:output method="xml" indent="yes" />    <xsl:param name="Boss_ID"></xsl:param>    <xsl:template match="OrgDoc">       <!-- template body goes here -->    </xsl:template>   </xsl:stylesheet> 

---

This simple XSLT sample will create just a small output document containing one XML node with its contents set to the value of your parameter. Have a try:

<?xml version="1.0" encoding="utf-8"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">   <xsl:output method="xml" indent="yes" />   <xsl:param name="Boss_ID"></xsl:param>    <xsl:template match="/">     <out>       <xsl:value-of select="$Boss_ID" />     </out>   </xsl:template>  </xsl:stylesheet>