Passing class method as parameter in Typescript

Question

I'm searching for a possibility to pass a class-method to a function which then can execute that function on an instance of that class. Something like that pseudocode: (note that this is an abstract example)

class Foo {     public somefunc() {         // do some     }     public anyfunc() {         // do any     } }  function bar(obj: Foo ,func: "Foo.method") {  // "that's what im looking for"     obj.func(); }  bar(new Foo(), Foo.somefunc);  // do some bar(new Foo(), Foo.anyfunc);  // do any 

Is there a possiblity to do this?

I know i could be doing something like that:

class Foo {     static somefunc(fooObj: Foo) {         // do some     }     static anyfunc(fooObj: Foo) {         // do any     } }  interface func {     (fooObj: Foo); }  function bar(obj: Foo, fn: func) {     fn(obj); }  bar(new Foo(), Foo.somefunc);  // do some bar(new Foo(), Foo.anyfunc);  // do any 

but that involves static functions which I don't want.

Answer 1

This doesn't compile-time check that the function came from a Foo, but does the rest:

class Foo {     public somefunc() {         // do some     }     public anyfunc() {         // do any     } }  function bar(obj: Foo ,func: () => void) {     func.call(obj); }  bar(new Foo(), Foo.prototype.somefunc);  // do some bar(new Foo(), Foo.prototype.anyfunc);  // do any