Passing Bash Variable to CURL

Question

when i give the values like this it works :

curl --silent \ --insecure \ -X POST \ -d '{"Name" : "Vikram"}' \ -H "Content-Type: application/json" \ $restUrl

but when i give it like this :

post="'{\"Name\" : \"Vikram\"}'"    
echo $post   // Prints '{"Name" : "Vikram"}'
echo ${post} // Prints '{"Name" : "Vikram"}'

but the following does not work and throws an 400 error:

curl --silent \ --insecure \ -X POST \ -d ${post} \ -H "Content-Type: application/json" \ $restUrl

Answer 1

It seems there are multiple issues.

1) To address the question asked by your title, when you use $post as an argument, the white space in its value causes it to be treated as multiple arguments by Bash. Try putting quotes around it so that it's treated as one argument.

2) I'm guessing you added single quotes to $post, in an attempt to have Bash treat it as a single parameter. Try removing the single quotes.

3) For me at least, all of the backslashes in the curl command were causing it to fail. Maybe you had it split across multiple lines and the copy/paste didn't translate that. I've removed them in my example below.

Putting all together:

post="{\"Name\" : \"Vikram\"}"
curl --silent --insecure -X POST -d "${post}" -H "Content-Type: application/json" $restUrl