I have some VERY inefficient code in which many lines appear 4 times as I go through permutations with "<" and ">" operations and a variety of variables and constants. It would seem that there is a way to write the function once and pass in the operators along with the necessarily changing values and"ref" variables. What technique do I have to learn? "Delegates" have been suggested but I don't see how to use them in this manner. This is in C# 2.0, VS2005, but if the technique is generic and can be used with C++ too, that would be great.
Request for some code: The following appears in many guises, with different "<" and ">" signs as well as a mix of "+" and "-" signs:
if (move[check].Ypos - move[check].height / 200.0D < LayoutManager.VISIO_HEIGHT - lcac_c.top)
{
move[check].Ypos = move[check].Ypos + adjust;
.
.
.
You can use the Action delegate type. Then you can use it like this: void MyAction() { } ErrorDBConcurrency(e, MyAction); If you do need parameters you can use a lambda expression.
Passing by reference enables function members, methods, properties, indexers, operators, and constructors to change the value of the parameters and have that change persist in the calling environment. To pass a parameter by reference with the intent of changing the value, use the ref , or out keyword.
It means we cannot pass a variable value as input using out parameter. Variables passed as out arguments do not have to be initialized before being passed in a method call. Even if it is initialized, this value cannot be accessed inside the method.
By default, C# does not allow you to choose whether to pass each argument by value or by reference. Value types are passed by value. Objects are not passed to methods; rather, references to objects are passed—the references themselves are passed by value.
In C++, use the std::less
and std::greater
functors. Both of these methods inherit std::binary_function
, so your generic function should accept instances of this type.
In .NET, the equivalent to std::binary_function
is Func<T, U, R>
. There are no equivalents to std::less
and std::greater
, but it is fairly trivial to create them. See the following example.
static class Functor
{
static Func<T, T, bool> Greater<T>()
where T : IComparable<T>
{
return delegate(T lhs, T rhs) { return lhs.CompareTo(rhs) > 0; };
}
static Func<T, T, bool> Less<T>()
where T : IComparable<T>
{
return delegate(T lhs, T rhs) { return lhs.CompareTo(rhs) < 0; };
}
}
Note, the above code uses the Func<>
class from .NET 3.5. If this is not acceptable, consider defining you own delegate.
C++ invocation example:
void DoWork(const std::binary_function<int, int, bool>& myOperator,
int arg1, int arg2)
{
if (myOperator(arg1, arg2)) { /* perform rest of work */ }
}
void main()
{
DoWork(std::less<int>(), 100, 200);
DoWork(std::greater<int>(), 100, 200);
}
C# invocation example:
void DoWork(Func<int, int, bool> myOperator, int arg1, int arg2)
{
if (myOperator(arg1, arg2)) { /* perform rest of work */ }
}
void main()
{
DoWork(Functor.Less<int>(), 100, 200);
DoWork(Functor.Greater<int>(), 100, 200);
}
EDIT: I corrected the example of the functor class as applying < or > operators to a generic type doesn't work (in the same manner as it does with C++ templates).
In C# use delegates for passing the "<
" and ">
" operation to the code that's doing the work.
C# Example:
public delegate bool BooleanOperatorDelegate(int a, int b)
class OperatorsImplementer {
public bool OperatorLess(int a, int b) {
return a < b;
}
}
class AnotherOperatorsImplementer {
public bool OperatorLess(int a, int b) {
return (a + 1) < (b - 1);
}
}
class OperatorUser {
int DoSomethingObscene(int a, int b, BooleanOperatorDelegate operator) {
if (operator(a, b)) {
return 5;
}
else {
return -5;
}
}
}
You should also check that the delegate you get as a paramater is not NULL.
This is the C method for doing so:
bool (*operator_func)(float a, float b)
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