ArrayList<String> list = new ArrayList<String>(); PreparedStatement pstmt = conn. prepareStatement("select * from employee where id in (?)"); Array array = conn. createArrayOf("VARCHAR", list. toArray()); pstmt.
Following is an elementary syntax structure to code for MySQL WHERE IN Array command in MySQL server to fetch information using array values and WHERE IN clause: SELECT ColumnName1, ColumnName2, …., ColumnNameNFROM TableNameWHERE ColumnName1 IN(ColumnName1_Value1, ColumnName1_Value2, ColumnName1_Value3);
The SQL WHERE clause is used to specify a condition while fetching the data from a single table or by joining with multiple tables. If the given condition is satisfied, then only it returns a specific value from the table.
BEWARE! This answer contains a severe SQL injection vulnerability. Do NOT use the code samples as presented here, without making sure that any external input is sanitized.
$ids = join("','",$galleries);
$sql = "SELECT * FROM galleries WHERE id IN ('$ids')";
Using PDO:[1]
$in = join(',', array_fill(0, count($ids), '?'));
$select = <<<SQL
SELECT *
FROM galleries
WHERE id IN ($in);
SQL;
$statement = $pdo->prepare($select);
$statement->execute($ids);
Using MySQLi [2]
$in = join(',', array_fill(0, count($ids), '?'));
$select = <<<SQL
SELECT *
FROM galleries
WHERE id IN ($in);
SQL;
$statement = $mysqli->prepare($select);
$statement->bind_param(str_repeat('i', count($ids)), ...$ids);
$statement->execute();
$result = $statement->get_result();
Explanation:
IN()
operator to check if a value exists in a given list.In general it looks like this:
expr IN (value,...)
We can build an expression to place inside the ()
from our array. Note that there must be at least one value inside the parenthesis or MySQL will return an error; this equates to making sure that our input array has at least one value. To help prevent against SQL injection attacks, first generate a ?
for each input item to create a parameterized query. Here I assume that the array containing your ids is called $ids
:
$in = join(',', array_fill(0, count($ids), '?'));
$select = <<<SQL
SELECT *
FROM galleries
WHERE id IN ($in);
SQL;
Given an input array of three items $select
will look like:
SELECT *
FROM galleries
WHERE id IN (?, ?, ?)
Again note that there is a ?
for each item in the input array. Then we'll use PDO or MySQLi to prepare and execute the query as noted above.
IN()
operator with stringsIt is easy to change between strings and integers because of the bound parameters. For PDO there is no change required; for MySQLi change str_repeat('i',
to str_repeat('s',
if you need to check strings.
[1]: I've omitted some error checking for brevity. You need to check for the usual errors for each database method (or set your DB driver to throw exceptions).
[2]: Requires PHP 5.6 or higher. Again I've omitted some error checking for brevity.
ints:
$query = "SELECT * FROM `$table` WHERE `$column` IN(".implode(',',$array).")";
strings:
$query = "SELECT * FROM `$table` WHERE `$column` IN('".implode("','",$array)."')";
Assuming you properly sanitize your inputs beforehand...
$matches = implode(',', $galleries);
Then just adjust your query:
SELECT *
FROM galleries
WHERE id IN ( $matches )
Quote values appropriately depending on your dataset.
Use:
select id from galleries where id in (1, 2, 5);
A simple for each
loop will work.
Flavius/AvatarKava's way is better, but make sure that none of the array values contain commas.
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