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Pass va_list or pointer to va_list?

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c

Suppose I have a function which takes variadic arguments (...) or a va_list passed from another such function. The main logic is in this function itself (let's call it f1), but I want to have it pass the va_list to another function (let's call it f2) which will determine the next argument type, obtain it using va_arg, and properly convert and store it for the caller to use.

Is it sufficient to pass a va_list to f2, or is it necessary to pass a pointer to va_list. Unless va_list is required to be an array type or else store its position data at the location the va_list object points to (rather than in the object itself), I can't see how passing it by value could allow the calling function (f1) to 'see' the changes the called function made by va_arg.

Can anyone shed light on this? I'm interested in what the standard requires, not what some particular implementation allows.

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R.. GitHub STOP HELPING ICE Avatar asked Jul 30 '10 07:07

R.. GitHub STOP HELPING ICE


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4 Answers

It looks like you'll need to pass a pointer to the va_list. For more info, see the C99 standard document section 7.15.In particular, bullet point 3 states:

The object ap may be passed as an argument to another function; if that function invokes the va_arg macro with parameter ap, the value of ap in the calling function is indeterminate and shall be passed to the va_end macro prior to any further reference to ap

[my italics]

Edit: Just noticed a footnote in the standard:

215) It is permitted to create a pointer to a va_list and pass that pointer to another function, in which case the original function may make further use of the original list after the other function returns

So you can pass a pointer to the va_list and do va_arg(*va_list_pointer) in the called function.

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JeremyP Avatar answered Sep 27 '22 16:09

JeremyP


In my understanding, you're supposed to pass the va_list directly (not a pointer to it). This seems to be supported by comp.lang.c:

"A va_list is not itself a variable argument list; it's really sort of a pointer to one. That is, a function which accepts a va_list is not itself varargs, nor vice versa. "

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S.C. Madsen Avatar answered Sep 27 '22 15:09

S.C. Madsen


I find the texts quite ambiguous on this question. The simplest is perhaps to look in the standard how predefined functions with va_list are supposed to receive it, e.g vsnprintf. And this is clearly by value and not by reference.

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Jens Gustedt Avatar answered Sep 27 '22 16:09

Jens Gustedt


You should pass a pointer to a va_list if you want to use it in a subfunction and then not have to immediately pass it to va_end afterwards. From C99:

It is permitted to create a pointer to a va_list and pass that pointer to another function, in which case the original function may make further use of the original list after the other function returns.

The standard allows this, however, on some 64-bit platforms where va_list is an array type, this does not work. As the address of an array is the same as the address of the first element of the array, passing a pointer to the va_list will segfault upon calling va_arg with that pointer to va_list as an argument.

A way to get around this is by receiving the va_list as an unconventional argument name (usually suffixed with one or more underscores) and then creating a new local va_list, like so:

#include <stdarg.h>

int vfoo(va_list ap_)
{
    int ret;
    va_list ap;
    va_copy(ap, ap_);
    ret = vbar(&ap);
    /* do other stuff with ap */
    va_end(ap);
    return ret;
}

This is the approach I use in my vsnprintf implementation to call other functions from it for formatting.

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S.S. Anne Avatar answered Sep 27 '22 16:09

S.S. Anne