I have this code that is supposed to create three child process' and each will perform a small mathematical operation. Then, the parent is supposed to use the results from all the child process' and get a final answer but I can't find a way to actually read the result from the child in the parent. Is there a way to do this?
#include <stdio.h>
#include <unistd.h>
#include <stdlib.h>
int main(void)
{
int pid1, pid2, pid3, status;
int a=1, b=2, c=5, d=4, e=6, f=3, g;
int t1, t2, t3;
printf("Hello World!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!\n");
printf("Here I am before use of forking\n");
printf("I am the PARENT process and pid is : %d\n",getpid());
pid1 = fork( );
if (pid1 == 0)
{
printf("\n\nHere I am just after child forking1\n");
printf("I am the Child process and pid1 is :%d\n",getpid());
printf("My parent's pid is :%d\n",getppid());
t1 = a+b;
printf("The answer for t1 is: %d\n", t1);
exit(0);
}
else
{
wait(&status);
printf("\nHere I am just after parent forking1\n");
printf("I am the Parent process and pid is: %d\n",getpid());
}
pid2 = fork( );
if (pid2 == 0)
{
printf("\n\nHere I am just after child forking2\n");
printf("I am the Child process and pid2 is :%d\n",getpid());
printf("My parent's pid is :%d\n",getppid());
t2 = c+d;
printf("The answer for t2 is: %d\n", t2);
exit(0);
}
else
{
wait(&status);
printf("\nHere I am just after parent forking2\n");
printf("I am the Parent process and pid is: %d\n",getpid());
}
pid3 = fork( );
if (pid3 == 0)
{
printf("\n\nHere I am just after child forking3\n");
printf("I am the Child process and pid3 is :%d\n",getpid());
printf("My parent's pid is :%d\n",getppid());
t3 = e/f;
printf("The answer for t3 is: %d\n", t3);
exit(0);
}
else
{
wait(&status);
printf("\nHere I am just after parent forkingALL\n");
printf("I am the Parent process and pid is: %d\n",getpid());
}
printf("\n\nThe final answer for t1 is: %d\n", t1);
printf("The final answer for t2 is: %d\n", t2);
printf("The final answer for t3 is: %d\n", t3);
g = t1*t2-t3;
printf("The final answer for g is: %d\n", g);
}
You can do this with a very easy technique, which is shared memory. I will give a complete example of how it works.
First, let's assume I want to write a program to print the first n
terms in Fibonacci series (and I know it is not that logical to do so, but it is an easy example so everyone can understand it).
n
termsn
to it#include <stdio.h>
#include <stdlib.h>
#include <sys/mman.h>
#include <fcntl.h>
#include <sys/stat.h>
void printFibo(int n, int *fibo)
{
int i;
for(i=0; i<=n; i++)
printf("%d -> %d\n" ,i, fibo[i]);
}
void computeFibo(int n, int *fibo)
{
int i;
fibo[0] = 0;
fibo[1] = 1;
for (i=2; i<=n; i++)
fibo[i] = fibo[i-1] + fibo[i-2];
}
int main(int argc, char *argv[])
{
pid_t childPID;
int status;
int shm_fd;
int* shared_memory;
int msize; // the size (in bytes) of the shared memory segment
const char *name = "FIBONACCI_SERIES";
int n;
if (argc!=2)
{
fprintf(stderr, "usage: %s <Fibonacci number to be generated>\n", argv[0]);
return -1;
}
n = atoi(argv[1]);
if (n < 0)
{
fprintf(stderr, "Illegal fibonacci number: %s\n", argv[1]);
return -2;
}
// calculating the array size based on the number of terms being passed from child to parent
msize = (n+2)*sizeof(int);
// open the memory
shm_fd = shm_open (name, O_CREAT | O_EXCL | O_RDWR, S_IRWXU | S_IRWXG);
if (shm_fd < 0)
{
fprintf(stderr,"Error in shm_open()");
return -3;
}
printf("Created shared memory object %s\n", name);
// attach the shared memory segment
ftruncate(shm_fd, msize);
printf("shmat returned\n");
// allocating the shared memory
shared_memory = (int *) mmap(NULL, msize, PROT_READ | PROT_WRITE, MAP_SHARED, shm_fd, 0);
if (shared_memory == NULL)
{
fprintf(stderr,"Error in mmap()");
return -3;
}
printf("Shared memory segment allocated correctly (%d bytes).\n", msize);
shared_memory[0] = n;
childPID=fork();
if ( childPID == -1 )
{
fprintf(stderr, "Cannot proceed. fork() error");
return -4;
}
if (childPID == 0)
{
// then we're the child process
computeFibo(shared_memory[0],shared_memory+1);
exit(0);
}
else
{
// parent will wait until the child finished
wait(&status);
// print the final results in the
printFibo(shared_memory[0], shared_memory+1);
// now detach the shared memory segment
shm_unlink(name);
}
return 0;
}
If you want to do it without using any way of communication i.e pipes, shared memory then you will have to use exit()
system call. The exit
system call return a signal that is then caught by wait()
system call in parent process. Here I am giving you a code in which I am sending a value from child to parent. One last thing you have to divide the signal caught by wait by 255 to get the exact value.
`
#include<unistd.h>
#include<stdio.h>
#include<stdlib.h>
#include<sys/types.h>
#include<sys/wait.h>
int main(int argc,char *argv[])
{
pid_t pid=fork();
if(pid==0)
{//child
int sum=5+7;
exit(sum);//sending exiting status or any value to parent
}
else
{//parent
int childval=-1;
wait(&childval);//catching signal sent by exit of(child)
printf("%d",childval/255);//changing signal to exact value
}
return 0;
}
`
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