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When I do
Hello=123 npm run a && npm run b && npm run c
I was expecting Hello=123 environment variable to be passed inside a, b and c process. But it turns out only a has the environment variable correctly set.
Is there any other ways that I can pass parameters all at once?
556
The set of environment names and the method for altering the environment list are implementation-defined. Depending on the implementation, multiple environment variables with the same name may be allowed and can cause unexpected results if a program cannot consistently choose the same value.
The easiest way to set environment variables in Bash is to use the “export” keyword followed by the variable name, an equal sign and the value to be assigned to the environment variable.
setenv is a built-in function of the C shell (csh). It is used to define the value of environment variables. If setenv is given no arguments, it displays all environment variables and their values. If only VAR is specified, it sets an environment variable of that name to an empty (null) value.
Try:
Hello=123 sh -c 'npm run a && npm run b && npm run c'
Better: use env before the whole line. This makes the one-liner work in both Bourne/POSIX and csh-derived shells:
env Hello=123 sh -c 'npm run a && npm run b && npm run c'
Your observation is that var=val foo && bar sets $var only in the environment of foo, not bar. That's correct. The solution is to set the environment for a command that in turn runs foo and bar: sh -c.
The other solution, of course, is simply:
Hello=123; export Hello # or export Hello=123 if using bash
npm run a && npm run b && npm run c
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