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You can send any data types of argument to a function (string, number, list, dictionary etc.), and it will be treated as the same data type inside the function.
The * symbol is used to pass a variable number of arguments to a function. Typically, this syntax is used to avoid the code failing when we don't know how many arguments will be sent to the function.
In Python, you can unpack list , tuple , dict (dictionary) and pass its elements to function as arguments by adding * to list or tuple and ** to dictionary when calling function.
function_that_needs_strings(*my_list) # works!
You can read all about it here.
Yes, you can use the *args (splat) syntax:
function_that_needs_strings(*my_list)
where my_list can be any iterable; Python will loop over the given object and use each element as a separate argument to the function.
See the call expression documentation.
There is a keyword-parameter equivalent as well, using two stars:
kwargs = {'foo': 'bar', 'spam': 'ham'}
f(**kwargs)
and there is equivalent syntax for specifying catch-all arguments in a function signature:
def func(*args, **kw):
# args now holds positional arguments, kw keyword arguments
Since Python 3.5 you can unpack unlimited amount of lists.
PEP 448 - Additional Unpacking Generalizations
So this will work:
a = ['1', '2', '3', '4']
b = ['5', '6']
function_that_needs_strings(*a, *b)
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