Logo Questions Linux Laravel Mysql Ubuntu Git Menu
 

Partly JSON unmarshal into a map in Go

Tags:

json

go

map

People also ask

How do you Unmarshal a map?

To convert a json to a map in Golang, use the json. Unmarshal() method. The Unmarshal() method parses the JSON-encoded data and stores the result in the value pointed to by the interface. If an interface is a nil or not a pointer, Unmarshal returns an InvalidUnmarshalError.

How does JSON Unmarshal work Golang?

To unmarshal a JSON array into a slice, Unmarshal resets the slice length to zero and then appends each element to the slice. As a special case, to unmarshal an empty JSON array into a slice, Unmarshal replaces the slice with a new empty slice.

How do you Unmarshal JSON?

To parse JSON, we use the Unmarshal() function in package encoding/json to unpack or decode the data from JSON to a struct. Unmarshal parses the JSON-encoded data and stores the result in the value pointed to by v. Note: If v is nil or not a pointer, Unmarshal returns an InvalidUnmarshalError.

What is the difference between Marshal and Unmarshal in Golang?

Unmarshal is the contrary of marshal. It allows you to convert byte data into the original data structure. In go, unmarshaling is handled by the json. Unmarshal() method.


This can be accomplished by Unmarshaling into a map[string]json.RawMessage.

var objmap map[string]json.RawMessage
err := json.Unmarshal(data, &objmap)

To further parse sendMsg, you could then do something like:

var s sendMsg
err = json.Unmarshal(objmap["sendMsg"], &s)

For say, you can do the same thing and unmarshal into a string:

var str string
err = json.Unmarshal(objmap["say"], &str)

EDIT: Keep in mind you will also need to export the variables in your sendMsg struct to unmarshal correctly. So your struct definition would be:

type sendMsg struct {
    User string
    Msg  string
}

Example: https://play.golang.org/p/OrIjvqIsi4-


Here is an elegant way to do similar thing. But why do partly JSON unmarshal? That doesn't make sense.

  1. Create your structs for the Chat.
  2. Decode json to the Struct.
  3. Now you can access everything in Struct/Object easily.

Look below at the working code. Copy and paste it.

import (
   "bytes"
   "encoding/json" // Encoding and Decoding Package
   "fmt"
 )

var messeging = `{
"say":"Hello",
"sendMsg":{
    "user":"ANisus",
    "msg":"Trying to send a message"
   }
}`

type SendMsg struct {
   User string `json:"user"`
   Msg  string `json:"msg"`
}

 type Chat struct {
   Say     string   `json:"say"`
   SendMsg *SendMsg `json:"sendMsg"`
}

func main() {
  /** Clean way to solve Json Decoding in Go */
  /** Excellent solution */

   var chat Chat
   r := bytes.NewReader([]byte(messeging))
   chatErr := json.NewDecoder(r).Decode(&chat)
   errHandler(chatErr)
   fmt.Println(chat.Say)
   fmt.Println(chat.SendMsg.User)
   fmt.Println(chat.SendMsg.Msg)

}

 func errHandler(err error) {
   if err != nil {
     fmt.Println(err)
     return
   }
 }

Go playground


Further to Stephen Weinberg's answer, I have since implemented a handy tool called iojson, which helps to populate data to an existing object easily as well as encoding the existing object to a JSON string. A iojson middleware is also provided to work with other middlewares. More examples can be found at https://github.com/junhsieh/iojson

Example:

func main() {
    jsonStr := `{"Status":true,"ErrArr":[],"ObjArr":[{"Name":"My luxury car","ItemArr":[{"Name":"Bag"},{"Name":"Pen"}]}],"ObjMap":{}}`

    car := NewCar()

    i := iojson.NewIOJSON()

    if err := i.Decode(strings.NewReader(jsonStr)); err != nil {
        fmt.Printf("err: %s\n", err.Error())
    }

    // populating data to a live car object.
    if v, err := i.GetObjFromArr(0, car); err != nil {
        fmt.Printf("err: %s\n", err.Error())
    } else {
        fmt.Printf("car (original): %s\n", car.GetName())
        fmt.Printf("car (returned): %s\n", v.(*Car).GetName())

        for k, item := range car.ItemArr {
            fmt.Printf("ItemArr[%d] of car (original): %s\n", k, item.GetName())
        }

        for k, item := range v.(*Car).ItemArr {
            fmt.Printf("ItemArr[%d] of car (returned): %s\n", k, item.GetName())
        }
    }
}

Sample output:

car (original): My luxury car
car (returned): My luxury car
ItemArr[0] of car (original): Bag
ItemArr[1] of car (original): Pen
ItemArr[0] of car (returned): Bag
ItemArr[1] of car (returned): Pen