On Android:
import android.net.Uri;
[...]
Uri uri=Uri.parse(url_string);
uri.getQueryParameter("para1");
Since Android M things have got more complicated. The answer of android.net.URI.getQueryParameter()
has a bug which breaks spaces before JellyBean.
Apache URLEncodedUtils.parse()
worked, but was deprecated in L, and removed in M.
So the best answer now is UrlQuerySanitizer
. This has existed since API level 1 and still exists. It also makes you think about the tricky issues like how do you handle special characters, or repeated values.
The simplest code is
UrlQuerySanitizer.ValueSanitizer sanitizer = UrlQuerySanitizer.getAllButNullLegal();
// remember to decide if you want the first or last parameter with the same name
// If you want the first call setPreferFirstRepeatedParameter(true);
sanitizer.parseUrl(url);
String value = sanitizer.getValue("paramName");
If you are happy with the default parsing behavior you can do:
new UrlQuerySanitizer(url).getValue("paramName")
but you should make sure you understand what the default parsing behavor is, as it might not be what you want.
On Android, the Apache libraries provide a Query parser:
http://developer.android.com/reference/org/apache/http/client/utils/URLEncodedUtils.html and http://hc.apache.org/httpcomponents-client-ga/httpclient/apidocs/org/apache/http/client/utils/URLEncodedUtils.html
public static Map<String, List<String>> getUrlParameters(String url)
throws UnsupportedEncodingException {
Map<String, List<String>> params = new HashMap<String, List<String>>();
String[] urlParts = url.split("\\?");
if (urlParts.length > 1) {
String query = urlParts[1];
for (String param : query.split("&")) {
String pair[] = param.split("=", 2);
String key = URLDecoder.decode(pair[0], "UTF-8");
String value = "";
if (pair.length > 1) {
value = URLDecoder.decode(pair[1], "UTF-8");
}
List<String> values = params.get(key);
if (values == null) {
values = new ArrayList<String>();
params.put(key, values);
}
values.add(value);
}
}
return params;
}
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