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Parsing an XML file using Element Tree

I have a large number of .xml files (about 70) and i need to extract some co-ordinates from them. Apparently the best way to do this is to parse the xml file using element tree. I am new to python (very very new!) and am having a difficult time understanding all of the documentation which comes with element tree! I was wondering if anyone had any code where they have used element tree or if anyone could explain to me how to go about it.. Thank you!

This is a sample from my XML file..

    <?xml version="1.0" encoding="UTF-8" ?> 
- <lev:Leveringsinformatie xmlns:lev="http://www.kadaster.nl/schemas/klic/20080722/leveringsinfo">
  <lev:Version>1.5</lev:Version> 
  <lev:Klicnummer>10G179900</lev:Klicnummer> 
  <lev:Ordernummer>0065491624</lev:Ordernummer> 
  <lev:RelatienummerGrondroerder>0000305605</lev:RelatienummerGrondroerder> 
  <lev:Leveringsvolgnummer>1</lev:Leveringsvolgnummer> 
  <lev:Meldingsoort>Graafmelding</lev:Meldingsoort> 
  <lev:DatumTijdAanvraag>2010-08-10T11:43:02.779+02:00</lev:DatumTijdAanvraag> 
  <lev:KlantReferentie>1207-0132-030 - 6</lev:KlantReferentie> 
- <lev:Locatie axisLabels="x y" srsDimension="2" srsName="epsg:28992" uomLabels="m m">
- <gml:exterior xmlns:gml="http://www.opengis.net/gml">
- <gml:LinearRing>
  <gml:posList>137800.0 484217.0 137796.0 484222.0 137832.0 483757.0 138178.0 483752.0 138174.0 484222.0 137800.0 484217.0</gml:posList> 
  </gml:LinearRing>
  </gml:exterior>
  </lev:Locatie>
- <lev:Pngformaat>
- <lev:OmsluitendeRechthoek xmlns:ns4="http://www.kadaster.nl/schemas/klic/20080722/madt" xmlns:bis="http://www.kadaster.nl/schemas/klic/20080722/klicnetbeheerdersinformatieservicetypes" xmlns:ns0="http://www.kadaster.nl/schemas/klic/20080722/gias" xmlns:ns7="http://www.kadaster.nl/schemas/klic/20080722/klicnetbeheerdersinformatieservicetypes" xmlns:madt="http://www.kadaster.nl/schemas/klic/20080722/madt" xmlns:gia="http://www.kadaster.nl/schemas/klic/20080722/gias" xmlns:klic="http://www.kadaster.nl/schemas/20080722/klic" xmlns:b="http://www.kadaster.nl/schemas/klic/20080722/bundelingtypes" xmlns:ns9="http://www.kadaster.nl/schemas/klic/20081010/bmkltypes" xmlns:gml="http://www.opengis.net/gml" xmlns:ns1="http://www.kadaster.nl/schemas/20080722/klic" xmlns:a="http://www.kadaster.nl/schemas/klic/20080722/bundelingservicetypes" xmlns:bmkl="http://www.kadaster.nl/schemas/klic/20081010/bmkltypes" xmlns:ns3="http://www.opengis.net/gml" xmlns:ns8="http://www.kadaster.nl/schemas/klic/20080722/knts">
- <gml:Envelope srsDimension="2" srsName="epsg:28992">
  <gml:lowerCorner>137796 483752</gml:lowerCorner> 
  <gml:upperCorner>138178 484222</gml:upperCorner> 
  </gml:Envelope>
  </lev:OmsluitendeRechthoek>
  <lev:PixelsBreed>5348</lev:PixelsBreed> 
  <lev:PixelsHoog>6580</lev:PixelsHoog> 
  </lev:Pngformaat>
- <lev:NetbeheerderLeveringen>
- <lev:NetbeheerderLevering>
  <lev:RelatienummerNetbeheerder>0000578695</lev:RelatienummerNetbeheerder> 
  <lev:Bedrijfsnaam>Gemeente Almere</lev:Bedrijfsnaam> 
  <lev:BedrijfsnaamAfkorting>Gemeente Almere</lev:BedrijfsnaamAfkorting> 

I need to extract the lower and upper corner co-ordinates (lowerCorner/upperCorner)

Update: Here is my full script:

from xml.etree import ElementTree as ET
import sys, string, os, arcgisscripting
gp = arcgisscripting.create(9.3)

workspace = "D:/J040083"
gp.workspace = workspace

for root, dirs, filenames in os.walk(workspace): # returms root, dirs, and files
    for filename in filenames:
        filename_split = os.path.splitext(filename) # filename and extensionname (extension in [1])
        filename_zero = filename_split[0]
        extension = str.upper(filename_split[1])

        try:
            first_2_letters = str.upper(filename_zero[0] + filename_zero[1])
        except:
            first_2_letters = "XX"

        if first_2_letters == "LI" and extension == ".XML":
            tree = ET.parse(workspace)
            print tree.find('//{http://www.opengis.net/gml}lowerCorner').text
            print tree.find('//{http://www.opengis.net/gml}upperCorner').text

I am now getting the error:

Message File Name Line Position
Traceback
D:\J040083\TXT_EXTRACTION.py 32
parse C:\Python25\Lib\xml\etree\ElementTree.py 862
parse C:\Python25\Lib\xml\etree\ElementTree.py 579
IOError: [Errno 13] Permission denied: 'D:/J040083'

and now i am REALLY confused because i am able to access these files with a different script which is almost exactly the same as this one!!

like image 476
Alice Duff Avatar asked Jan 18 '11 10:01

Alice Duff


1 Answers

ElementTree can be tricky when namespaces are involved. The element you are looking for are named <gml:lowerCorner> and <gml:upperCorner>. Searching higher in the XML data, gml is defined as an XML namespace: xmlns:gml="http://www.opengis.net/gml". The way to find a subelement of the XML tree is as follows:

from xml.etree import ElementTree as ET
tree = ET.parse('file.xml')
print tree.find('//{http://www.opengis.net/gml}lowerCorner').text
print tree.find('//{http://www.opengis.net/gml}upperCorner').text

Output

137796 483752
138178 484222

Explanation

Using ElementTree's XPath support, // selects all subelements on all levels of the tree. ElementTree uses {url}tag notation for a tag in a specific namespace. gml's URL is http://www.opengis.net/gml. .text retrieves the data in the element.

Note that // is a shortcut to finding a nested node. The full path of upperCorner in ElementTree's syntax is actually:

{http://www.kadaster.nl/schemas/klic/20080722/leveringsinfo}Pngformaat/{http://www.kadaster.nl/schemas/klic/20080722/leveringsinfo}OmsluitendeRechthoek/{http://www.opengis.net/gml}Envelope/{http://www.opengis.net/gml}upperCorner
like image 76
Mark Tolonen Avatar answered Sep 27 '22 19:09

Mark Tolonen