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Parsing a possibly nested braced item using a grammar

Tags:

grammar

raku

I am starting to write BibTeX parser. The first thing I would like to do is to parse a braced item. A braced item could be an author field or a title for example. There might be nested braces within the field. The following code does not handle nested braces:

use v6;

my $str = q:to/END/;
  author={Belayneh, M. and Geiger, S. and Matth{\"{a}}i, S.K.}, 
  END

$str .= chomp;

grammar ExtractBraced {
    rule TOP {
        'author=' <braced-item> .*
    }
    rule braced-item      { '{' <-[}]>* '}' }
}

ExtractBraced.parse( $str ).say;

Output:

「author={Belayneh, M. and Geiger, S. and Matth{\"{a}}i, S.K.},」
 braced-item => 「{Belayneh, M. and Geiger, S. and Matth{\"{a}」

Now, in order to make the parser accept nested braces, I would like to keep a counter of the number of opening braces currently parsed and when encountering a closing brace, we decrement the counter. If the counter reaches zero, we assume that we have parsed the complete item.

To follow this idea, I tried to split up the braced-item regex, to implement an grammar action on each char. (The action method on the braced-item-char regex below should then handle the brace-counter):

grammar ExtractBraced {
    rule TOP {
        'author=' <braced-item> .*
    }
    rule braced-item      { '{' <braced-item-char>* '}' }
    rule braced-item-char { <-[}]> }
}

However, suddenly now the parsing fails. Probably a silly mistake, but I cannot see why it should fail now?

like image 234
Håkon Hægland Avatar asked Nov 05 '17 17:11

Håkon Hægland


1 Answers

Without knowing how you want the resultant data to look I would change it to look something like this:

my $str = 「author={Belayneh, M. and Geiger, S. and Matth{\"{a}}i, S.K.},」;

grammar ExtractBraced {
    token TOP {
        'author='
        $<author> = <.braced-item>
        .*
    }
    token braced-item {
       '{' ~ '}'

           [
           || <- [{}] >+
           || <.before '{'> <.braced-item>
           ]*
    }
}

ExtractBraced.parse( $str ).say;
「author={Belayneh, M. and Geiger, S. and Matth{\"{a}}i, S.K.},」
 author => 「{Belayneh, M. and Geiger, S. and Matth{\"{a}}i, S.K.}」

If you want a bit more structure It might look a bit more like this:

my $str = 「author={Belayneh, M. and Geiger, S. and Matth{\"{a}}i, S.K.},」;

grammar ExtractBraced {
    token TOP {
        'author='
        $<author> = <.braced-item>
        .*
    }
    token braced-part {
        || <- [{}] >+
        || <.before '{'> <braced-item>
    }
    token braced-item {
        '{' ~ '}'
            <braced-part>*
    }
}

class Print {
    method TOP ($/){
        make $<author>.made
    }
    method braced-part ($/){
        make $<braced-item>.?made // ~$/
    }
    method braced-item ($/){
        make [~] @<braced-part>».made
    }
}


my $r = ExtractBraced.parse( $str, :actions(Print) );
say $r;
put();
say $r.made;
「author={Belayneh, M. and Geiger, S. and Matth{\"{a}}i, S.K.},」
 author => 「{Belayneh, M. and Geiger, S. and Matth{\"{a}}i, S.K.}」
  braced-part => 「Belayneh, M. and Geiger, S. and Matth」
  braced-part => 「{\"{a}}」
   braced-item => 「{\"{a}}」
    braced-part => 「\"」
    braced-part => 「{a}」
     braced-item => 「{a}」
      braced-part => 「a」
  braced-part => 「i, S.K.」

Belayneh, M. and Geiger, S. and Matth\"ai, S.K.

Note that the + on <-[{}]>+ is an optimization, as well as <before '{'>, both can be omitted and it will still work.

like image 157
Brad Gilbert Avatar answered Oct 06 '22 23:10

Brad Gilbert