Parsing a char to u32

Question

As the questions states, how do I achieve this?

If I have a code like this:

let a = "29";
for c in a.chars() {
    println!("{}", c as u32);
}

What I obtain is the unicode codepoints for 2 and 9:

• 50
• 57

What I want is to parse those characters into the actual numbers.

Answer 1

char::to_digit(radix) does that. radix denotes the "base", i.e. 10 for the decimal system, 16 for hex, etc.:

let a = "29";
for c in a.chars() {
    println!("{:?}", c.to_digit(10));
}

It returns an Option, so you need to unwrap() it, or better: expect("that's no number!"). You can read more about proper error handling in the appropriate chapter of the Rust book.