Parametrize template by function name c++11

Question

Having the following functions

void print(int a) { cout << a << endl; }
void print(std::string a) { cout << a << endl; }

You can do the following template

template <class T> void printT(T a) { print(a); }

Is there some mechanism to parametrize the function name? Something like this:

template <class T, class F> void anyT(T a) { F(a); }

I don't need to be a function template, just some mechanism to achieve the same.

Answer 1

Yes, you could pass the caller as a function pointer that takes as input T like below:

template <class T> void anyT(T a, void(*f)(T)) {
  f(a);
}

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