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Pandas Groupby Multiple Columns - Top N

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I've got a fun one! And I've tried to find a duplicate question but was unsuccessful...

My dataframe consists of all United States and territories for years 2013-2016 with several attributes.

>>> df.head(2)
     state  enrollees  utilizing  enrol_age65  util_age65  year
1  Alabama     637247     635431       473376      474334  2013
2   Alaska      30486      28514        21721       20457  2013

>>> df.tail(2)
     state               enrollees  utilizing  enrol_age65  util_age65  year
214  Puerto Rico          581861     579514       453181      450150  2016
215  U.S. Territories      24329      16979        22608       15921  2016

I want to groupby year and state, and show the top 3 states (by 'enrollees' or 'utilizing' - does not matter) for each year.

Desired Output:

                                       enrollees  utilizing
year state                                                 
2013 California                          3933310    3823455
     New York                            3133980    3002948
     Florida                             2984799    2847574
...
2016 California                          4516216    4365896
     Florida                             4186823    3984756
     New York                            4009829    3874682

So far I've tried the following:

df.groupby(['year','state'])['enrollees','utilizing'].sum().head(3)

Which yields just the first 3 rows in the GroupBy object:

                 enrollees  utilizing
year state                           
2013 Alabama        637247     635431
     Alaska          30486      28514
     Arizona        707683     683273

I've also tried a lambda function:

df.groupby(['year','state'])['enrollees','utilizing']\
  .apply(lambda x: np.sum(x)).nlargest(3, 'enrollees')

Which yields the absolute largest 3 in the GroupBy object:

                 enrollees  utilizing
year state                           
2016 California    4516216    4365896
2015 California    4324304    4191704
2014 California    4133532    4011208

I think it may have to do with the indexing of the GroupBy object, but I am not sure...Any guidance would be appreciated!

like image 701
atlas Avatar asked Feb 08 '19 16:02

atlas


2 Answers

Well, you could do something not that pretty.

First getting a list of unique years using set():

years_list = list(set(df.year))

Create a dummy dataframe and a function to concat that I've made in the past:

def concatenate_loop_dfs(df_temp, df_full, axis=0):
    """
    to avoid retyping the same line of code for every df.
    the parameters should be the temporary df created at each loop and the concatenated DF that will contain all
    values which must first be initialized (outside the loop) as df_name = pd.DataFrame(). """ 

if df_full.empty:
    df_full = df_temp
else:
    df_full = pd.concat([df_full, df_temp], axis=axis)

return df_full

creating the dummy final df

df_final = pd.DataFrame()

Now you'll loop for each year and concating into the new DF:

for year in years_list:
    # The query function does a search for where
    # the @year means the external variable, in this case the input from loop
    # then you'll have a temporary DF with only the year and sorting and getting top3
    df2 = df.query("year == @year")

    df_temp = df2.groupby(['year','state'])['enrollees','utilizing'].sum().sort_values(by="enrollees", ascending=False).head(3)
    # finally you'll call our function that will keep concating the tmp DFs
    df_final = concatenate_loop_dfs(df_temp, df_final)

and done.

print(df_final)
like image 153
mrbTT Avatar answered Sep 21 '22 20:09

mrbTT


You then need to sort your GroupBy object .sort_values('enrollees), ascending=False

like image 29
mbass Avatar answered Sep 20 '22 20:09

mbass