Pandas: Filtering multiple conditions

Question

I'm trying to do boolean indexing with a couple conditions using Pandas. My original DataFrame is called df. If I perform the below, I get the expected result:

temp = df[df["bin"] == 3]
temp = temp[(~temp["Def"])]
temp = temp[temp["days since"] > 7]
temp.head()

However, if I do this (which I think should be equivalent), I get no rows back:

temp2 = df[df["bin"] == 3]
temp2 = temp2[~temp2["Def"] & temp2["days since"] > 7]
temp2.head()

Any idea what accounts for the difference?

Answer 1

Use () because operator precedence:

temp2 = df[~df["Def"] & (df["days since"] > 7) & (df["bin"] == 3)]

Alternatively, create conditions on separate rows:

cond1 = df["bin"] == 3    
cond2 = df["days since"] > 7
cond3 = ~df["Def"]

temp2 = df[cond1 & cond2 & cond3]

Sample:

df = pd.DataFrame({'Def':[True] *2 + [False]*4,
                   'days since':[7,8,9,14,2,13],
                   'bin':[1,3,5,3,3,3]})

print (df)
     Def  bin  days since
0   True    1           7
1   True    3           8
2  False    5           9
3  False    3          14
4  False    3           2
5  False    3          13


temp2 = df[~df["Def"] & (df["days since"] > 7) & (df["bin"] == 3)]
print (temp2)
     Def  bin  days since
3  False    3          14
5  False    3          13

Answer 2

OR

 df_train[(df_train["fold"]==1) | (df_train["fold"]==2)]

AND

 df_train[(df_train["fold"]==1) & (df_train["fold"]==2)]

Answer 3

Alternatively, you can use the method query:

df.query('not Def & (`days since` > 7) & (bin == 3)')

Answer 4

If you want multiple conditions:

Del_Det_5k_top_10 = Del_Det[(Del_Det['State'] == 'NSW') & (Del_Det['route'] == 2) |
                            (Del_Det['State'] == 'VIC') & (Del_Det['route'] == 3)]