I'm trying to generate a date range of monthly data where the day is always at the beginning of the month:
pd.date_range(start='1/1/1980', end='11/1/1991', freq='M')
This generates 1/31/1980
, 2/29/1980
, and so on. Instead, I just want 1/1/1980
, 2/1/1980
,...
I've seen other question ask about generating data that is always on a specific day of the month, with answers saying it wasn't possible, but beginning of month surely must be possible!
date_range() function. The date_range() function is usede to get a fixed frequency DatetimeIndex. Left bound for generating dates. Right bound for generating dates.
Specifying the valuesSpecify start and end , with the default daily frequency. Specify start and periods , the number of periods (days). Specify end and periods , the number of periods (days). Specify start , end , and periods ; the frequency is generated automatically (linearly spaced).
Using Pandas to Create a List of Range of Dates in Python. We will use the date_range() function of pandas in which we will pass the start date and the number of days after that (known as periods). Here we have also used the datetime library to format the date so that we can output the date in this format DD-MM-YY .
You can do this by changing the freq
argument from 'M'
to 'MS'
:
d = pandas.date_range(start='1/1/1980', end='11/1/1990', freq='MS') print(d)
This should now print:
DatetimeIndex(['1980-01-01', '1980-02-01', '1980-03-01', '1980-04-01', '1980-05-01', '1980-06-01', '1980-07-01', '1980-08-01', '1980-09-01', '1980-10-01', ... '1990-02-01', '1990-03-01', '1990-04-01', '1990-05-01', '1990-06-01', '1990-07-01', '1990-08-01', '1990-09-01', '1990-10-01', '1990-11-01'], dtype='datetime64[ns]', length=131, freq='MS', tz=None)
Look into the offset aliases part of the documentation. There it states that 'M'
is for the end of the month (month end frequency) while 'MS'
for the beginning (month start frequency).
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