Pandas - Create dataframe with only one row from dictionary containing lists

Question

I have this dictionary:

d = {'val_1': [1,2,3,4,5], 'val_2': 4}

And I want to create a pandas DataFrame from this with only one row.

When I do:

import pandas as pd
df = pd.DataFrame(d)
print(df)

I get 5 rows:

    val_1   val_2
0   1       4
1   2       4
2   3       4
3   4       4
4   5       4

However, when I append it to the existing dataframe, I get the behavior I want.

import pandas as pd
df = pd.DataFrame(d)
df = df.append(d, ignore_index=True)
print(df)

    val_1           val_2
0   1               4
1   2               4
2   3               4
3   4               4
4   5               4
5   [1, 2, 3, 4, 5] 4

How can I create the dataframe from the dict, and get only one row as in the append case?

    val_1             val_2
0   [1, 2, 3, 4, 5]   4

Answer 1

Wrap the values in a list:

pd.DataFrame({k: [v] for k, v in d.items()})
#             val_1   val_2
#0  [1, 2, 3, 4, 5]       4

Answer 2

You can start with pd.Series instead:

pd.Series(d).to_frame().T

             val_1 val_2
0  [1, 2, 3, 4, 5]     4