I am wondering if there are any efficient methods or one-liner that, given a pandas DatetimeIndex date1, return a DatetimeIndex date2 that is the first day of the next month?
For example, if date1 is '2011-09-30' then date2 is '2011-10-01'?
I have tried this one liner
df.index.to_period("M").to_timestamp('M')
But this seems only able to return the "last day of the same month". Is it possible to do some datetime arithmetic here?
Thanks!
You can use pd.offsets.MonthBegin()
In [261]: d = pd.to_datetime(['2011-09-30', '2012-02-28'])
In [262]: d
Out[262]: DatetimeIndex(['2011-09-30', '2012-02-28'], dtype='datetime64[ns]', freq=None)
In [263]: d + pd.offsets.MonthBegin(1)
Out[263]: DatetimeIndex(['2011-10-01', '2012-03-01'], dtype='datetime64[ns]', freq=None)
You'll find a lot of examples in the official Pandas docs
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