overloaded member functions for a particular template specialisation

Question

I have a class tPoint that would be implemented having different base types so

template<typename T>class tPoint{
   T x;
   T y;
public:
   void Set(T ix, T iy){x=ix;y=iy;}
};

When the type T is int, tPoint<int>, I want a special Set(float, float) so I can round the values before assignation.

I thought that with specialisation I could:

template<> void tPoint<int>::Set(float ix,float iy){x=ix+.5; y=iy+.5;}

This way the compiler complains that there's no matching function in the class definition.

But if I declare in the class Set(float,float) then it says that's already defined (when it compiles for T =float)

I hope I made myself clear, what would be a clean approach to this or I'm doing something wrong? thanks!

Answer 1

You need to specialize the class, like this:

template<> class tPoint<int>{
   int x;
   int y;
public:
   void Set(int ix, int iy){x=ix;y=iy;}
   void Set(float ix, float iy){x = ix+0.5; y = iy+0.5;}
};