I'm working on a sql query that is passed a list of values as a parameter, like
select *
from ProductGroups
where GroupID in (24,12,7,14,65)
This list is constructed of relations used througout the database, and must be kept in this order.
I would like to order the results by this list. I only need the first result, but it could be the one with GroupId 7 in this case.
I can't query like
order by (24,12,7,14,65).indexOf(GroupId)
Does anyone know how to do this?
Additional info:
Building a join works and running it in the mssql query editor, but...
Due to limitiations of the software sending the query to mssql, I have to pass it to some internal query builder as 1 parameter, thus "24,12,7,14,65". And I don't know upfront how many numbers there will be in this list, could be 2, could be 20.
The ORDER BY keyword is used to sort the result-set in ascending or descending order. The ORDER BY keyword sorts the records in ascending order by default. To sort the records in descending order, use the DESC keyword.
Syntax: SELECT * FROM table_name ORDER BY column_name; For Multiple column order, add the name of the column by which you'd like to sort records first. The column that is entered at first place will get sorted first and likewise.
An ORDER BY command cannot be used in a subquery, although the main query can use an ORDER BY. The GROUP BY command can be used to perform the same function as the ORDER BY in a subquery.
You can also order by on a CASE:
select *
from ProductGroups
where GroupID in (24,12,7,14,65)
order by case GroupId
when 7 then 1 -- First in ordering
when 14 then 2 -- Second
else 3
end
Use a table variable or temporary table with an identity column, feed in your values and join to that, e.g.
declare @rank table (
ordering int identity(1,1)
, number int
)
insert into @rank values (24)
insert into @rank values (12)
insert into @rank values (7)
insert into @rank values (14)
insert into @rank values (65)
select pg.*
from ProductGroups pg
left outer join
@rank r
on pg.GroupId = r.number
order by
r.ordering
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