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Does anyone know if there exist some kind of selector to select al the elements from a matched set but the one given by the indicated index. E.g.:
$("li").neq(2).size(); Supposing that there were 5 elements, the last statement would give you 4, and would contain all the <li> elements but the second one in the DOM.
547
eq() returns it as a jQuery object, meaning the DOM element is wrapped in the jQuery wrapper, which means that it accepts jQuery functions. . get() returns an array of raw DOM elements. You may manipulate each of them by accessing its attributes and invoking its functions as you would on a raw DOM element.
jQuery eq() Method The eq() method returns an element with a specific index number of the selected elements. The index numbers start at 0, so the first element will have the index number 0 (not 1).
The not() is an inbuilt function in jQuery which is just opposite to the filter() method. This function will return all the element which is not matched with the selected element with the particular “id” or “class”.
myclass:eq(1)" ) selects the second element in the document with the class myclass, rather than the first. In contrast, :nth-child(n) uses 1-based indexing to conform to the CSS specification. Prior to jQuery 1.8, the :eq(index) selector did not accept a negative value for index (though the . eq(index) method did).
Use not:
$('li').not(':eq(2)'); Alright, it's just
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