Menu
I want to see if this statement is false:
if twData is Array {
}
isnt and isnot don't seem to exist.
This doesn't work:
if (twData is Array) == false {
}
So I'm not sure exactly how to do this, other than the less clean:
if twData is Array {
} else {
//Code goes here
}
276
Code and Explanation: Using the 'if not' Python statement to check if it negates the output of an 'if' statement. As you can see, the code under the 'if' block was returned although the condition returned false. This is because the 'not' operator negated its value.
you probably should be using a list (or array in other languages), not separate variables. There's no need for else: pass . You can just leave out the else: statement if there's nothing to do. The letters function never returns anything, what are you expecting print(letters(word)) to print?
Use the IF function, one of the logical functions, to return one value if a condition is true and another value if it's false. For example: =IF(A2>B2,"Over Budget","OK") =IF(A2=B2,B4-A4,"")
Yes, it is valid. The else is an optional part. During the program execution, the statements written inside the if block will only be executed when the condition mentioned is true. Otherwise, if the condition is false, the next consecutive lines after the if block will be executed.
If you know the generic type stored in the array, then you should make it explicit:
if !(twData is Array<Int>) {
// Do something
}
If instead you just want to know if it's an array regardless of the generic type, then you have to use NSArray:
if !(twData is NSArray) {
}
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With
