I have to open settings app from my app if gps is not enabled in iPhone. I have used the following code. It works well in iOS simulator but it does not work in iPhone. May I know is there any problem in this code.
if (![CLLocationManager locationServicesEnabled]) { int (*openApp)(CFStringRef, Boolean); void *hndl = dlopen("/System/Library/PrivateFrameworks/SpringBoardServices.framework/SpringBoardServices"); openApp = (int(*)(CFStringRef, Boolean)) dlsym(hndl, "SBSLaunchApplicationWithIdentifier"); openApp(CFSTR("com.apple.Preferences"), FALSE); dlclose(hndl); }
To open up the settings in Swift code, first get the URL from the openSettingsURLString property that Apple provides. Then open that URL using the openURL method. To put it on an alert dialog with two options, open settings or dismiss, you could follow this code example.
Good news :
You can open settings apps programmatically like this (works only from iOS8 onwards).
If you are using Swift 3.0:
UIApplication.shared.open(URL(string: UIApplicationOpenSettingsURLString)!)
If you are using Objective-C:
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:UIApplicationOpenSettingsURLString]];
For other lower versions (less than iOS8) its not possible to programatically open the settings app.
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