Open file by filename wildcard

Question

I have a directory of text files that all have the extension .txt. My goal is to print the contents of the text file. I wish to be able use the wildcard *.txt to specify the file name I wish to open (I'm thinking along the lines of something like F:\text\*.txt?), split the lines of the text file, then print the output.

Here is an example of what I want to do, but I want to be able to change somefile when executing my command.

f = open('F:\text\somefile.txt', 'r') for line in f:     print line, 

I had checked out the glob module earlier, but I couldn't figure out how to actually do anything to the files. Here is what I came up with, not working.

filepath = "F:\irc\as\*.txt" txt = glob.glob(filepath)  lines = string.split(txt, '\n') #AttributeError: 'list' object has no attribute 'split' print lines 

Answer 1

import os import re path = "/home/mypath" for filename in os.listdir(path):     if re.match("text\d+.txt", filename):         with open(os.path.join(path, filename), 'r') as f:             for line in f:                 print line, 

Although you ignored my perfectly fine solution, here you go:

import glob path = "/home/mydir/*.txt" for filename in glob.glob(path):     with open(filename, 'r') as f:         for line in f:             print line,