Open application with bundle identifier

Question

Is it possible to open a application from our application with bundle identifier. Suppose I have two apps installed on device one with com.test.app1 and com.test.app2. Can I open app1 from my app2.

I know about openUrl method. for that I have to register url scheme in info.plist. and then i can use following method:

[[UIApplication sharedApplication] openUrl:[NSURL urlWithString:@"myApp1://"]];

But what if I didn't register url scheme or don't know the registered url.

Any idea..?

Answer 1

You can use private API to do that

Class LSApplicationWorkspace_class = objc_getClass("LSApplicationWorkspace");
NSObject * workspace = [LSApplicationWorkspace_class performSelector:@selector(defaultWorkspace)];
BOOL isopen = [workspace performSelector:@selector(openApplicationWithBundleID:) withObject:@"com.apple.mobilesafari"];