I am trying to replicate IDLE's alt
+ m
command (open a module in the sys
path) in Notepad++. I like Notepad++ for editing (rather than IDLE), but this is one feature I cannot find.
When alt+m
is pressed, I want it to run a program that asks for a module (that's fairly straightforward, so I can do that). My problem is finding the module and then opening it in Notepad++, not simply running the program. In addition, I want it to open in the same instance (same window) in Notepad++, not a new instance.
I've tried this:
import os
f = r"D:\my_stuff\Google Drive\Modules\nums.py"
os.startfile(f, 'notepad++.exe')
However, I get this error:
Traceback (most recent call last):
File '_filePath_', line 3, in <module>
os.startfile(f, 'notepad++.exe')
OSError: [WinError 1155] No application is associated with the specified file for this operation: 'D:\\my_stuff\\Google Drive\\Modules\\nums.py'
How can I fix this?
Also, given a string, such as 'nums.py'
, how can I find the full path of it? It's going to be in one of two folders: 'D:\\my_stuff\\Google Drive\\Modules'
or 'C:\\Python27\Lib'
(it could also be in various subfolders in the 'Lib'
folder). Alternatively, I could simply do:
try:
fullPath = r'D:\\my_stuff\\Google Drive\\Modules\\' + f
# method of opening file in Notepad++
except (IOError, FileNotFoundError):
fullPath = r'C:\\Python27\\Lib\\' + f
# open in Notepad++
This doesn't account for subfolders and seems rather clunky. Thanks!
If your .py files will be associated w/ notepad++ the os.startfile(f, 'notepad++.exe')
will work for you (see ftype).
Unless, you would like to create this association , the following code will open notepad ++ for you:
import subprocess
subprocess.call([r"c:\Program ...Notepad++.exe", r"D:\my_stuff\Google Drive\Modules\nums.py"])
Reference: subprocess.call()
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