Open a File in default File explorer and highlight it using JavaFX or plain Java

Question

I wish to do what the title says.

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Part Solution:

For example in Windows you can use the code below to open a file in the default explorer and highlight it.

(although it needs modification for files containing spaces):

/**
 * Opens the file with the System default file explorer.
 *
 * @param path the path
 */
public static void openFileLocation(String path) {
    if (InfoTool.osName.toLowerCase().contains("win")) {
        try {
            Runtime.getRuntime().exec("explorer.exe /select," + path);
        } catch (IOException ex) {
            Main.logger.log(Level.WARNING, ex.getMessage(), ex);
        }
    }
}

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Useful Links:

Links which are similar but no way dublicates or not answered:

How to use java code to open Windows file explorer and highlight the specified file?

Open a folder in explorer using Java

How can I open the default system browser from a java fx application?

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More explanation:

• Is there a way to do it using JavaFX ?

    If not at least i need a link or some way to make the app system  
     independence.I mean i don't know the default explorer for every OS     
     that the application is going to work , i need a link or help doing that.
  

• Do i need to write a ton of code to do this?

• Is out there any library for doing that?

• Do Java9 support that?

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Finally:

It is very strange that for so common things i can't find answers and libraries .

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Example of highlighted or selected in Windows 10:

Answer 1

Windows

Runtime.getRuntime().exec("explorer /select, <file path>")

Linux

Runtime.getRuntime().exec("xdg-open <file path>");

MacOS

Runtime.getRuntime().exec("open -R <file path>");