I know this is easy but i m just not able to debug it.
I am dynamically creating 3 LinearLayouts and adding them to a scroll View . I am adding a Button "ins" to the top of 3 linearlayout.
The problem is that on clicking the ins Button , its on clicklistener is being called 3 times . code:
package com.integrated.mpr;
import android.app.Activity;
import android.app.Dialog;
import android.util.Log;
import android.util.TypedValue;
import android.view.View;
import android.view.View.OnClickListener;
import android.view.ViewGroup.LayoutParams;
import android.widget.Button;
import android.widget.EditText;
import android.widget.LinearLayout;
import android.widget.ScrollView;
import android.widget.TextView;
public class Page1 extends Activity implements OnClickListener{
static int pos = new Choose().n;
static String partname;
int i;
int[][] id = new int[pos][5];
@Override
protected void onCreate(Bundle savedInstanceState) {
// TODO Auto-generated method stub
super.onCreate(savedInstanceState);
int p =0;
for(int i =0;i<3;i++){
for(int j =0;j<5;j++){
p++;
}
}
ScrollView sv = new ScrollView(this);
LinearLayout ll = new LinearLayout(this);
ll.setOrientation(LinearLayout.VERTICAL);
int resid = getResources().getIdentifier("background", "drawable", getPackageName());
ll.setBackgroundResource(resid);
Button ins = new Button(this);
ins.setText("Instructions");
ins.setOnClickListener(this);
ins.setId(5000);
ll.addView(ins);
for(i =0;i<3;i++){
LinearLayout llay = new LinearLayout(this);
llay.setOrientation(LinearLayout.VERTICAL);
TextView tv = new TextView(this);
tv.setText("enter the " +(i+1)+" position name");
EditText et = new EditText(this);
et.setId(id[i][0]);
Button starta = new Button(this);
starta.setText("Record 1");
starta.setId(id[i][1]);
starta.setOnClickListener(this);
Button startb = new Button(this);
startb.setText("Record 2");
startb.setId(id[i][2]);
startb.setOnClickListener(this);
Button startc = new Button(this);
startc.setText("Record 3");
startc.setId(id[i][3]);
startc.setOnClickListener(this);
Button stop = new Button(this);
stop.setText("Submit");
stop.setId(id[i][4]);
stop.setOnClickListener(this);
TextView tv1 = new TextView(this);
tv1.setVisibility(llay.INVISIBLE);
llay.addView(tv);
llay.addView(et);
llay.addView(starta);
llay.addView(startb);
llay.addView(startc);
llay.addView(stop);
llay.addView(tv1);
ll.addView(llay);
}
Button bcon = new Button(this);
bcon.setText("Continue");
bcon.setId(10000);
bcon.setOnClickListener(this);
ll.addView(bcon);
sv.addView(ll);
this.setContentView(sv);
}
@Override
public void onClick(View v) {
// TODO Auto-generated method stub
if(v.getId()==5000){
Log.d("ins", "called");
Context mContext = Page1.this;
Dialog dialog = new Dialog(mContext);
dialog.setTitle("Instructions");
dialog.setContentView(R.layout.instructiondialog);
dialog.show();
}
}
}
}
I know definitely , there is some problem in the code of OnCreate but what it is ? Help please
Can anyone further explain how to set the button aligned o the right of screen , that is how to set its layout gravity?
I am not sure about what exactly you want to achieve.but you can set the flag.if flag value is 1 then only process onClick else not.
Below snippet will help you.
Yes but you will have to somehow reset that flag to 1.
@Override
public void onClick(View v)
{
// TODO Auto-generated method stub
if(v.getId()==5000)
{
if(flag)
{
Log.d("ins", "called");
Context mContext = Page1.this;
Dialog dialog = new Dialog(mContext);
dialog.setTitle("Instructions");
dialog.setContentView(R.layout.instructiondialog);
dialog.show();
}
flag=0;
}
}
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