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OLS with pandas: datetime index as predictor

I would like to use pandas OLS function to fit a trendline to my data Series. Does anyone knows how to use the datetime index from the pandas Series as predictor in the OLS?

For example, let say that I have a simple time series:

>>> ts
2001-12-31    19.828763
2002-12-31    20.112191
2003-12-31    19.509116
2004-12-31    19.913656
2005-12-31    19.701649
2006-12-31    20.022819
2007-12-31    20.103024
2008-12-31    20.132712
2009-12-31    19.850609
2010-12-31    19.290640
2011-12-31    19.936210
2012-12-31    19.664813
Freq: A-DEC

I would like to do an OLS on it using the index as predictor:

model = pd.ols(y=ts,x=ts.index,intercept=True)

But as x is a list of datetime index, the function returns an error. Anyone has an idea?

I could use linregress from scipy.stats but I wonder if it is possible with Pandas.

Thanks, Greg

like image 324
leroygr Avatar asked Jan 16 '13 15:01

leroygr


1 Answers

The problem is that you cannot pass an Index to ols.
Change it to a Series:

In [153]: ts
Out[153]: 
2011-01-01 00:00:00    19.828763
2011-01-01 01:00:00    20.112191
2011-01-01 02:00:00    19.509116
Freq: H, Name: 1

In [158]: type(ts.index)
Out[158]: pandas.tseries.index.DatetimeIndex


In [154]: df = ts.reset_index()

In [155]: df
Out[155]: 
                index          1
0 2011-01-01 00:00:00  19.828763
1 2011-01-01 01:00:00  20.112191
2 2011-01-01 02:00:00  19.509116

In [160]: type(df['index'])
Out[160]: pandas.core.series.Series


In [156]: model = pd.ols(y=df[1], x=df['index'], intercept=True)

In [163]: model
Out[163]: 

-------------------------Summary of Regression Analysis-------------------------

Formula: Y ~ <x> + <intercept>

Number of Observations:         3
Number of Degrees of Freedom:   1

R-squared:        -0.0002
Adj R-squared:    -0.0002

Rmse:              0.3017

F-stat (1, 2):       -inf, p-value:     1.0000

Degrees of Freedom: model 0, resid 2

-----------------------Summary of Estimated Coefficients------------------------
      Variable       Coef    Std Err     t-stat    p-value    CI 2.5%   CI 97.5%
--------------------------------------------------------------------------------
             x     0.0000     0.0000       0.00     0.9998    -0.0000     0.0000
     intercept     0.0000 76683.4934       0.00     1.0000 -150299.6471 150299.6471
---------------------------------End of Summary---------------------------------
like image 74
tzelleke Avatar answered Sep 27 '22 20:09

tzelleke