Octave: find the minimum value in a row, and also it's index

Question

How would one find the minimum value in each row, and also the index of the minimum value?

octave:1> a = [1 2 3; 9 8 7; 5 4 6]
a =

   1   2   3
   9   8   7
   5   4   6

Answer 1

This is hard to find in the documentation. https://www.gnu.org/software/octave/doc/v4.0.3/Utility-Functions.html

octave:2> [minval, idx] = min(a, [], 2)
minval =

   1
   7
   4

idx =

   1
   3
   2

Answer 2

If A is your matrix, do:

[colMin, row] = min(A);
[rowMin, col] = min(A');

colMin will be the minimum values in each row, and col the column indexes. rowMin will be the minimum values in each column, and row the row indexes.

To find the index of the smallest element:

[colMin, colIndex] = min(min(A)); 
[minValue, rowIndex] = min(A(:,colIndex))

Answer 3

Suppose X is a matrix
row, col = Row and Column index of minimum value

[min_value, column_index] = min(X(:))
[row, col] = ind2sub(size(X),column_index)