Obtaining only the filename when using OpenFileDialog property "FileName"

Question

I am trying to include only the filename of the file I've selected in the OpenFileDialog in the label1.Text property, but I haven't found a solution yet. I know I could use a method from the string class on the ofd instance to filter out the whole path to the file, but I would like to know if a smarter/quicker way exists?

OpenFileDialog ofd = new OpenFileDialog(); ofd.Title = "Find song"; ofd.Filter = "MP3 files|*.mp3"; ofd.InitialDirectory = @"C:\"; if (ofd.ShowDialog() == DialogResult.OK) {    label1.Text = "" + ofd.FileName +""; } 

Answer 1

Use OpenFileDialog.SafeFileName

OpenFileDialog.SafeFileName Gets the file name and extension for the file selected in the dialog box. The file name does not include the path.

Answer 2

Use: Path.GetFileName Method

var onlyFileName = System.IO.Path.GetFileName(ofd.FileName);