I would like to know how to parse a hex string, representing a number, in Objective-C. I am willing to use both an objective, or a C-based method, either is fine.
example:
#01FFFFAB
should parse into the integer: 33554347
Any help would be appreciated!
Joshua Weinberg's answer is mostly correct, however the 0x
prefix is optional when scanning hexadecimal integers. If you have a string in the format #01FFFFAB
, you can still use NSScanner
, but you can skip the first character.
unsigned result = 0;
NSScanner *scanner = [NSScanner scannerWithString:@"#01FFFFAB"];
[scanner setScanLocation:1]; // bypass '#' character
[scanner scanHexInt:&result];
you can use NSScanner for this
unsigned int outVal;
NSScanner* scanner = [NSScanner scannerWithString:@"0x01FFFFAB"];
[scanner scanHexInt:&outVal];
outVal
will contain the int you're looking for. The 0x is optional.
strtol() is your friend.
It converts a string to a long, and you can pass the base of the number in. Strip that # sign off first though, or pass to strtol a pointer to the first numerical character.
You can use the below line for conversion. Its just one line code:
NSString *hexString = @"01FFFFAB";
length = (UInt64)strtoull([hexString UTF8String], NULL, 16);
NSLog(@"The required Length is %d", length);
Happy Coding!!!
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