Numpy Array Get row index searching by a row

Question

I am new to numpy and I am implementing clustering with random forest in python. My question is:

How could I find the index of the exact row in an array? For example

[[ 0.  5.  2.]  [ 0.  0.  3.]  [ 0.  0.  0.]] 

and I look for [0. 0. 3.] and get as result 1(the index of the second row).

Any suggestion? Follows the code (not working...)

    for index, element in enumerate(leaf_node.x):         for index_second_element, element_two in enumerate(leaf_node.x):             if (index <= index_second_element):                 index_row = np.where(X == element)                 index_column = np.where(X == element_two)                 self.similarity_matrix[index_row][index_column] += 1 

Answer 1

Why not simply do something like this?

>>> a array([[ 0.,  5.,  2.],        [ 0.,  0.,  3.],        [ 0.,  0.,  0.]]) >>> b array([ 0.,  0.,  3.])  >>> a==b array([[ True, False, False],        [ True,  True,  True],        [ True,  True, False]], dtype=bool)  >>> np.all(a==b,axis=1) array([False,  True, False], dtype=bool)  >>> np.where(np.all(a==b,axis=1)) (array([1]),)