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numeric_limits<T>::min();
numeric_limits<T>::lowest();
What is the different between the value returned by both functions?
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The std::numeric_limits ::digits function is used to find the number of radix digits that the data type can represent without loss of precision.
Data types that supports std::numeric_limits() in C++ std::numeric_limits<int>::max() gives the maximum possible value we can store in type int. std::numeric_limits<unsigned int>::max()) gives the maximum possible value we can store in type unsigned int.
This function is used to find the smallest non-zero denormalized value. Parameter: The function std::numeric_limits<T>::denorm_min() does not accept any parameter. Return Value: The functionstd::numeric_limits<T>::denorm_min() returns the smallest nonzero denormalized value of data type T.
Paragraph 18.3.2.4 of the C++11 Standard specifies:
static constexpr T min() noexcept;1 Minimum finite value.
2 For floating types with denormalization, returns the minimum positive normalized value.
3 Meaningful for all specializations
[...]
static constexpr T lowest() noexcept;6 A finite value x such that there is no other finite value y where y < x.
7 Meaningful for all specializations in which is_bounded != false.
Footnote 197 then adds the relevant remark:
lowest()is necessary because not all floating-point representations have a smallest (most negative) value that is the negative of the largest (most positive) finite value.
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For floating point types min returns the smallest finite number that is > 0 representable in the type (i.e. the number having the lowest absolute value != 0) while lowest returns the smallest finite number that is representable (i.e. the negative number of maximal absolute value that is less than -infinity).
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