c++ string array initialization

Question

I know I can do this in C++:

string s[] = {"hi", "there"}; 

But is there anyway to delcare an array this way without delcaring string s[]?

e.g.

void foo(string[] strArray){   // some code }  string s[] = {"hi", "there"}; // Works foo(s); // Works  foo(new string[]{"hi", "there"}); // Doesn't work 

Answer 1

In C++11 you can. A note beforehand: Don't new the array, there's no need for that.

First, string[] strArray is a syntax error, that should either be string* strArray or string strArray[]. And I assume that it's just for the sake of the example that you don't pass any size parameter.

#include <string>  void foo(std::string* strArray, unsigned size){   // do stuff... }  template<class T> using alias = T;  int main(){   foo(alias<std::string[]>{"hi", "there"}, 2); } 

Note that it would be better if you didn't need to pass the array size as an extra parameter, and thankfully there is a way: Templates!

template<unsigned N> void foo(int const (&arr)[N]){   // ... } 

Note that this will only match stack arrays, like int x[5] = .... Or temporary ones, created by the use of alias above.

int main(){   foo(alias<int[]>{1, 2, 3}); } 

Answer 2

Prior to C++11, you cannot initialise an array using type[]. However the latest c++11 provides(unifies) the initialisation, so you can do it in this way:

string* pStr = new string[3] { "hi", "there"}; 

See http://www2.research.att.com/~bs/C++0xFAQ.html#uniform-init