Number of digits in exponent

Question

Is it possible to set the number of digits to be used for printing the exponent of a floating-point number? I want to set it to 3.

Currently,

f = 0.0000870927939438012
>>> "%.14e"%f
'8.70927939438012e-05'
>>> "%0.14e"%f
'8.709279e-005'

What I want to print is: '8.70927939438012e-005'

Answer 1

There is a no way to control that, best way is to write a function for this e.g.

def eformat(f, prec, exp_digits):     s = "%.*e"%(prec, f)     mantissa, exp = s.split('e')     # add 1 to digits as 1 is taken by sign +/-     return "%se%+0*d"%(mantissa, exp_digits+1, int(exp))  print eformat(0.0000870927939438012, 14, 3) print eformat(1.0000870927939438012e5, 14, 3) print eformat(1.1e123, 4, 4) print eformat(1.1e-123, 4, 4) 

Output:

8.70927939438012e-005 1.00008709279394e+005 1.1000e+0123 1.1000e-0123 

Answer 2

You can use np.format_float_scientific

from numpy import format_float_scientific  f = 0.0000870927939438012  format_float_scientific(f, exp_digits=3) # prints '8.70927939438012e-005'  format_float_scientific(f, exp_digits=5, precision=2) #prints '8.71e-00005'