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Matplotlib coord. sys origin to top left

How can I flip the origin of a matplotlib plot to be in the upper-left corner - as opposed to the default lower-left? I'm using matplotlib.pylab.plot to produce the plot (though if there is another plotting routine that is more flexible, please let me know).

I'm looking for the equivalent of the matlab command: axis ij;

Also, I've spent a couple hours surfing matplotlib help and google but haven't come up with an answer. Some info on where I could have looked up the answer would be helpful as well.

like image 643
Nate Avatar asked Aug 28 '09 20:08

Nate


3 Answers

The easiest way is to use:

plt.gca().invert_yaxis() 

After you plotted the image. Origin works only for imshow.

like image 120
G M Avatar answered Sep 16 '22 16:09

G M


axis ij just makes the y-axis increase downward instead of upward, right? If so, then matplotlib.axes.invert_yaxis() might be all you need -- but I can't test that right now.

If that doesn't work, I found a mailing post suggesting that

setp(gca(), 'ylim', reversed(getp(gca(), 'ylim')))

might do what you want to resemble axis ij.

like image 42
Mark Rushakoff Avatar answered Sep 18 '22 16:09

Mark Rushakoff


For an image or contour plot, you can use the keyword origin = None | 'lower' | 'upper' and for a line plot, you can set the ylimits high to low.

from pylab import *
A = arange(25)/25.
A = A.reshape((5,5))

figure()
imshow(A, interpolation='nearest', origin='lower')

figure()
imshow(A, interpolation='nearest')

d = arange(5)
figure()
plot(d)
ylim(5, 0)

show()
like image 21
tom10 Avatar answered Sep 16 '22 16:09

tom10