Menu
I have two tasks for an assignment, one return the number of bits in type int on any machine. I thought I would write my function like so:
int CountIntBitsF() {
int x = sizeof(int) / 8;
return x;
}
Does that look right?
The second part is to return the number of any bits of any data type with a macro, and the macro can be taken from limits.h. I looked up limits.h on my machine, and also http://www.opengroup.org/onlinepubs/007908799/xsh/limits.h.html, but I don't think I really understand how any of those would return the number of bits in any data type. Any thoughts? Thanks.
981
Fundamental Data TypesA byte is eight bits, a word is 2 bytes (16 bits), a doubleword is 4 bytes (32 bits), and a quadword is 8 bytes (64 bits). Figure 29-2 shows the byte order of each of the fundamental data types when referenced as operands in memory.
The char type takes 1 byte of memory (8 bits) and allows expressing in the binary notation 2^8=256 values. The char type can contain both positive and negative values. The range of values is from -128 to 127.
int , long , ptr , and off_t are all 32 bits (4 bytes) in size. int is 32 bits in size. long , ptr , and off_t are all 64 bits (8 bytes) in size.
The fundamental unit of storage is a char. It is not always 8 bits wide. CHAR_BIT is defined in limits.h and has the number of bits in a char.
195
It's *, not /.
As for the second part, see the "Numerical Limits" section.
26
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With
