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I couldn't find a solution to this problem in Swift (all of them are Objective-C, and they deal with pointers which I don't think exist in Swift in the same form). Is there any way to convert a NSData object into an array of bytes in the form of [Uint8] in Swift?
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NSData is toll-free bridged with its Core Foundation counterpart, CFData . See Toll-Free Bridging for more information on toll-free bridging. Important. The Swift overlay to the Foundation framework provides the Data structure, which bridges to the NSData class and its mutable subclass NSMutableData .
In Swift a byte is called a UInt8—an unsigned 8 bit integer. A byte array is a UInt8 array. In ASCII we can treat chars as UInt8 values. With the utf8 String property, we get a UTF8View collection. We can convert this to a byte array.
You can avoid first initialising the array to placeholder values, if you go through pointers in a slightly convoluted manner, or via the new Array constructor introduced in Swift 3:
let data = "foo".data(using: .utf8)! // new constructor: let array = [UInt8](data) // …or old style through pointers: let array = data.withUnsafeBytes { [UInt8](UnsafeBufferPointer(start: $0, count: data.count)) } Array(UnsafeBufferPointer(start: UnsafePointer<UInt8>(data.bytes), count: data.length)) If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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