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The following code won't compile. Why?
class A
{
int j;
void f( int i = this->j );
}
Edit, for clarity. This is what I was trying to do, using less lines of code...
class A
{
void f( int i ){};
void f( );
int j;
};
void A::f()
{
f( j );
}
610
The Python "SyntaxError: non-default argument follows default argument" occurs when we define a function with a positional parameter that follows a default parameter. To solve the error, make sure to specify all default parameters after the positional parameters of the function.
Default argument cannot be provided for pointers to functions.
Default arguments are only allowed in the parameter lists of function declarations and lambda-expressions, (since C++11) and are not allowed in the declarations of pointers to functions, references to functions, or in typedef declarations.
Answer: d) is a bad idea because the default [] will accumulate data and the default [] will change with subsequent calls.
Default argument values are bound at compile time.
"this" is only defined at run time, so can't be used.
See here for a fuller explanation: Must default function parameters be constant in C++?
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