According to this answer, an iterator
must be implicitly convertible to const_iterator
. Since that is true, as we can see happening in insert_or_assign()
, then why in C++17 was a new signature added to std::map::erase()
?
In C++11, we have iterator erase( const_iterator pos );
In C++17, we now have iterator erase( iterator pos );
Wasn't the C++11 signature good enough to receive iterator
and const_iterator
?
map::clear() function is an inbuilt function in C++ STL, which is defined in header file. clear() is used to remove all the content from the associated map container. This function removes all the values and makes the size of the container as 0.
map erase() function in C++ STL map::erase() is a built-in function in C++ STL which is used to erase element from the container. It can be used to erase keys, elements at any specified position or a given range.
No it doesn't free the memory if it is a naked pointer. You need to ensure that the memory is deallocated appropriately.
Time complexity: k*log(n) where n is size of map, k is no. of elements inserted.
There's a potential ambiguity with erase(const key_type& key)
when you pass an iterator
. Consider the case where the key_type
is something like std::any
.
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