Need advice implementing a binary heap structure in Scala

Question

Well I'm just learning Scala and I'm trying to implement some algorithms and data structures.

I wrote some code that aims to transform a Vector in a linear binary heap. For instance:

Vector(8,3,4,6,2,5,7,9) is transformed to Vector(9,8,7,6,2,4,5,3)

In this way, given index i, its parent is at: (i-1)/2 or (i-2)/2 depending on i being odd or pair.

I leave the code here, What I'm looking for is some advice on how could I improve my implementation. Or even try it out in another completely different direction.

You can use this like: new Heap(Vector(8,3,4,6,2,5,7,9))

class Heap(vs: Vector[Int]) {
  val heap = build()

  private def build():Vector[Int] = {   
    ((1 until vs.length) foldLeft Vector[Int](vs.head)) ( (accu, idx) =>
        fixFrom(accu :+ vs(idx), idx) )
  }

  private def fixFrom(heapToFix:Vector[Int], idx: Int): Vector[Int] = {
      val parentIndex = parent(idx)
      if(parentIndex == -1 || heapToFix(idx) <= heapToFix(parentIndex)) heapToFix
      else {
          val nextToFix = (heapToFix.updated(parentIndex, heapToFix(idx))) take idx 
          val fixed = fixFrom(nextToFix, parentIndex)
          val swap = heapToFix.updated(idx, heapToFix(parentIndex))
          fixed ++ (swap drop idx)
      }
  }

  def children(parentIndex: Int) = 
    (valid(2*parentIndex + 1), valid(2*parentIndex + 2))

  def parent(childIndex: Int) = 
    if(childIndex % 2 == 0) valid((childIndex-2)/2)
    else valid((childIndex-1)/2)

  def valid(idx:Int) =
    if(idx >= 0 && idx < vs.length) idx else -1

  override def toString = heap mkString " "
}

Update 1: Taking the advices below, I've done some changes:

import math.Ordering.Implicits._

class Heap[T: Ordering](vs: Vector[T]) {
  val heap = build()

  private def build():Vector[T] = 
    ((0 until vs.length) foldLeft Vector.empty[T]) ( (accu, idx) =>
        fixUp(accu :+ vs(idx), idx) )

  @annotation.tailrec       
  private def fixUp(h:Vector[T], idx: Int): Vector[T] = {
      val parentIdx = parent(idx)
      if(parentIdx < 0 || h(idx) <= h(parentIdx)) h
      else fixUp(h.updated(parentIdx, h(idx)).updated(idx, h(parentIdx)), parentIdx)
  }

  def parent(idx: Int) = (idx-1) >> 1

  override def toString = heap mkString " "
}

Answer 1

import scala.math.Ordering.Implicits._

def insert[T : Ordering](heap: Vector[T], newItem: T) = {
  @annotation.tailrec
  def siftUp(h: Vector[T], idx: Int):Vector[T] = {
    val parentIdx = (idx - 1) >> 1
    if(parentIdx < 0 || h(parentIdx) > h(idx)) h
    else siftUp(h.updated(parentIdx, h(idx)).updated(idx, h(parentIdx)), parentIdx)
  }

  siftUp(heap :+ newItem, heap.length)
}
def heapify[T: Ordering](vs: Vector[T]) = vs.foldLeft(Vector.empty[T])(insert)

assert(heapify(Vector(8, 3, 4, 6, 2, 5, 7, 9)) == Vector(9, 8, 7, 6, 2, 4, 5, 3))