Just learning about UNION queries - what a timesaver - but having trouble with grouping.
I have the following statement:
(SELECT `shops`.shpUserAdded AS userName, count(`shops`.shpID) AS shpCount, "" AS prdCount FROM `shops` GROUP BY shpUserAdded ASC)
UNION
(SELECT `products`.prdUserAdded AS userName, "" AS shpCount, count(`products`.prdID) AS prdCount FROM `products` GROUP BY prdUserAdded ASC)
but this gives me the results from the first query followed by the results of the second query, without combining the usernames:
userName|merCount|prdCount
| 8|
Jane | 1|
Derek | 1|
James | 22|
| | 3
Jane | | 4
Derek | | 5
James | | 21
I tried (but obviously got #1248 - Every derived table must have its own alias):
SELECT userName, shpCount, prdCount FROM
((SELECT `shops`.shpUserAdded AS userName, count(`shops`.shpID) AS shpCount, "" AS prdCount FROM `shops` GROUP BY shpUserAdded ASC)
UNION
(SELECT `products`.prdUserAdded AS userName, "" AS shpCount, count(`products`.prdID) AS prdCount FROM `products` GROUP BY prdUserAdded ASC))
GROUP BY userName ASC
I can't seem to figure out naming the derived table(s) without wiping out the data from either the shpCount or prdCount column - any suggestions? I'm probably going to feel stupid but thereyago!
Solved it (really this time)! :)
SELECT Users.userName, Products.prdCount, Shops.shpCount FROM
(
(
(SELECT `Shops`.shpAddU AS userName FROM `Shops` GROUP BY shpAddU ASC)
UNION
(SELECT `Products`.prdAddU AS userName FROM `Products` GROUP BY prdAddU ASC)
) AS Users
)
LEFT JOIN
(SELECT prdAddU AS userName, count(*) AS prdCount FROM `Products` GROUP BY prdAddU) as Products ON Users.userName = Products.userName
LEFT JOIN
(SELECT shpAddU AS userName, count(*) AS shpCount FROM `Shops` GROUP BY shpAddU) as Shops ON Users.userName = Shops.userName
Not everything is a union -- in this case it's a join on the subqueries:
SELECT shpUserAdded AS userName, merCount, prdCount
FROM (SELECT shpUserAdded, count(*) AS shpCount FROM shops GROUP BY shpUserAdded ASC) AS s
JOIN (SELECT prdUserAdded, count(*) AS prdCount FROM products GROUP BY prdUserAdded ASC) AS p
ON (shpUserAdded = prdUserAdded);
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