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I have a database of users. I would like to create a graph based on userbase growth. The query I have now is:
SELECT DATE(datecreated), count(*) AS number FROM users WHERE DATE(datecreated) > '2009-06-21' AND DATE(datecreated) <= DATE(NOW()) GROUP BY DATE(datecreated) ORDER BY datecreated ASC This returns almost what I want. If we get 0 users one day, that day is not returned as a 0 value, it is just skipped and the next day that has at least one user is returned. How can I get something like (psuedo-response):
date1 5 date2 8 date3 0 date4 0 date5 9 etc... where the dates with zero show up in sequential order with the rest of the dates?
Thanks!
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If you need to select rows from a MySQL database' table in a date range, you need to use a command like this: SELECT * FROM table WHERE date_column >= '2014-01-01' AND date_column <= '2015-01-01'; Of course you need to change: table.
The symbol <> in MySQL is same as not equal to operator (!=). Both gives the result in boolean or tinyint(1). If the condition becomes true, then the result will be 1 otherwise 0.
SELECT DATE(r1. reportdate) + INTERVAL 1 DAY AS missing_date FROM Reports r1 LEFT OUTER JOIN Reports r2 ON DATE(r1. reportdate) = DATE(r2. reportdate) - INTERVAL 1 DAY WHERE r1.
You have a few options: SELECT * FROM table WHERE id != 4; SELECT * FROM table WHERE NOT id = 4; SELECT * FROM table WHERE id <> 4; Also, considering perhaps sometime in the future you may want to add/remove id's to this list, perhaps another table listing id's which you don't want selectable would be a good idea.
I hope you will figure out the rest.
select * from ( select date_add('2003-01-01 00:00:00.000', INTERVAL n5.num*10000+n4.num*1000+n3.num*100+n2.num*10+n1.num DAY ) as date from (select 0 as num union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) n1, (select 0 as num union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) n2, (select 0 as num union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) n3, (select 0 as num union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) n4, (select 0 as num union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) n5 ) a where date >'2011-01-02 00:00:00.000' and date < NOW() order by date With
select n3.num*100+n2.num*10+n1.num as date you will get a column with numbers from 0 to max(n3)*100+max(n2)*10+max(n1)
Since here we have max n3 as 3, SELECT will return 399, plus 0 -> 400 records (dates in calendar).
You can tune your dynamic calendar by limiting it, for example, from min(date) you have to now().
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