Being a self-taught newbie, I created a large problem for myself. Before inserting data in to my database, I've been converting apostrophes (') in a string, to double quotes (""), instead of the required back-slash and apostrophe (\'), which MySQL actually requires.
Before my table grows more than the 200,000 rows it already is, I thought it was best to rectify this issue immediately. So I did some research and found the SQL REPLACE function, which is great, but I'm now confused.
In ASP, I was doing this:
str = Replace(str,"'","""")
If I look at my database in SQL Workbench, the symbol I converted is now a single quote ("), which has confused me a little. I understand why it changed from double to single, but I don't know which one I'm meant to be changing now.
To go through and rectify my problem using SQL REPLACE, do I now convert single quotes (") to back-slash and apostrophes (\') or do I convert double quotes ("") to back-slash and apostrophes (\')?
For example, this:
SQL = " SELECT REPLACE(myColumn,"""","\'") FROM myTable "
or this:
SQL = " SELECT REPLACE(myColumn,""","\'") FROM myTable "
I hope I explained myself well, any suggestions gratefully received as always. Any queries about my question, please comment.
Many thanks
-- UPDATE --
I have tried the following queries but still fail to change the ( " ) in the data:
SELECT REPLACE(caption,'\"','\'') FROM photos WHERE photoID = 3371 SELECT REPLACE(caption,'"','\'') FROM photos WHERE photoID = 3371 SELECT REPLACE(caption,'""','\'') FROM photos WHERE photoID = 3371
Yet if I search:
SELECT COUNT(*) FROM photos WHERE caption LIKE '%"%'
I get 16,150 rows.
-- UPDATE 2 --
Well, I have created a 'workaround'. I managed to convert an entire column pretty quickly writing an ASP script, using this SQL:
SELECT photoID, caption FROM photos WHERE caption LIKE '%""%';
and then in ASP I did:
caption = Replace(caption,"""","\'")
But I would still like to know why I couldn't achieve that with SQL?
SQL Server REPLACE() FunctionThe REPLACE() function replaces all occurrences of a substring within a string, with a new substring. Note: The search is case-insensitive.
To replace, use the REPLACE() MySQL function. Since you need to update the table for this, use the UPDATE() function with the SET clause.
Just running the SELECT
statement will have no effect on the data. You have to use an UPDATE
statement with the REPLACE
to make the change occur:
UPDATE photos SET caption = REPLACE(caption,'"','\'')
Here is a working sample: http://sqlize.com/7FjtEyeLAh
Replace below characters
~ ! @ # $ % ^ & * ( ) _ + ` - = { } | [ ] \ : " ; ' < > ? , .
with this SQL
SELECT note as note_original, REPLACE( REPLACE( REPLACE( REPLACE( REPLACE( REPLACE( REPLACE( REPLACE( REPLACE( REPLACE( REPLACE( REPLACE( REPLACE( REPLACE( REPLACE( REPLACE( REPLACE( REPLACE( REPLACE( REPLACE( REPLACE( REPLACE( REPLACE( REPLACE( REPLACE( REPLACE( REPLACE( REPLACE( REPLACE( REPLACE( REPLACE( REPLACE( REPLACE(note, '\"', ''), '.', ''), '?', ''), '`', ''), '<', ''), '=', ''), '{', ''), '}', ''), '[', ''), ']', ''), '|', ''), '\'', ''), ':', ''), ';', ''), '~', ''), '!', ''), '@', ''), '#', ''), '$', ''), '%', ''), '^', ''), '&', ''), '*', ''), '_', ''), '+', ''), ',', ''), '/', ''), '(', ''), ')', ''), '-', ''), '>', ''), ' ', '-'), '--', '-') as note_changed FROM invheader
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